-0.05
The Economist
Jun 14, 2020
Nov 17, 2004(21y)
Nov 17, 2026(149d)
Combat
Kills0
Losses5
Efficiency0%
ISK
Destroyed0
Lost19.96m
ISK Eff.0%
Solo
Solo Kills0
Solo Ratio0%
Final Blows0
Points0
Other
NPC Losses0
NPC Loss Ratio0%
Avg Kills/Day0.00
ActivityInactive
Caldari
Deteis
-0.05
The Economist
Last Active
Jun 14, 2020
Birthday
Nov 17, 2004 (21 years old)
Next Birthday
Nov 17, 2026 (149 days)
Combat
Kills0
Losses5
Efficiency0%
Danger Ratio100%
ISK
Destroyed0
Lost19.96m
ISK Efficiency0%
Balance-19957256
Solo
Solo Kills0
Solo Ratio0%
Final Blows0
Points0
Other
NPC Losses0
NPC Loss Ratio0%
Avg Kills/Day0.00
ActivityInactive
No data available
Bio
Manipulating the universe since 1856
*
Proving that 3 + 2 = 0
Assume A + B = C, and assume A = 3 and B = 2.
Multiply both sides of the equation A + B = C by (A + B).
We obtain A\xb2 + 2AB + B\xb2 = C(A + B)
Rearranging the terms we have
A\xb2 + AB - AC = - AB - B\xb2 + BC
Factoring out (A + B - C), we have
A(A + B - C) = - B(A + B - C)
Dividing both sides by (A + B - C),
we get A = - B,
or A + B = 0,
which is to say 3 + 2 = 0
.....so there.
*
*
Proving that 3 + 2 = 0
Assume A + B = C, and assume A = 3 and B = 2.
Multiply both sides of the equation A + B = C by (A + B).
We obtain A\xb2 + 2AB + B\xb2 = C(A + B)
Rearranging the terms we have
A\xb2 + AB - AC = - AB - B\xb2 + BC
Factoring out (A + B - C), we have
A(A + B - C) = - B(A + B - C)
Dividing both sides by (A + B - C),
we get A = - B,
or A + B = 0,
which is to say 3 + 2 = 0
.....so there.
*
Dashboard
Stats
Kills0
Losses0
Efficiency0%
ISK Destroyed0
ISK Lost0
ISK Efficiency0%
Solo Kills0
Solo Losses0
NPC Losses0
Blob Factor0
Active TimezoneUSTZ
Final Blows0
Points0
Activity Heat Map (EVE Time)
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Intel Profile
PlaystyleSolo (0 kills)
Avg Fleet: -